I have a command that produce a output like this:
$./command1
word1 word2 word3
I want to pass this three words as arguments to another command like this:
$ command2 word1 word2 word3
How to pass command1 output as three different arguments $1 $2 $3 to command2 ?
You can use xargs, with the -t flag xargs will be verbose and prints the commands it executes:
./command1 | xargs -t -n1 command2
-n1 defines the maximum arguments passed to every call of command2. This will execute:
command2 word1
command2 word2
command2 word3
If you want all as argument of one call of command2 use that:
./command1 | xargs -t command2
That calls command2 with 3 arguments:
command2 word1 word2 word3
You want 'command substitution', i.e: embed output of one command in anouther
command2 $(command1)
Traditionally this can also be done as:
command2 `command1`
but this usage isn't normally recommended, as you can't nest them.
For example:
test.sh:
#!/bin/bash
echo a b c
test2.sh
#!/bin/bash
echo $2
USE:
./test2.sh $(./test.sh)
b
